document.write( "Question 1128224: If (sqrt 3 - 1) is a root of the equation 2x^2-2kx+4 = 0, then k equals... \n" ); document.write( "

Algebra.Com's Answer #744707 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the roots be $\"+r%5B1%5D+\"$ and $\"+r%5B2%5D+\"$
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\n" ); document.write( " $\"+2x%5E2+-+2k%2Ax+%2B++4+=+0++\"$
\n" ); document.write( " $\"+x%5E2+-+k%2Ax+%2B+2+=+0+\"$
\n" ); document.write( " $\"+k+=+r%5B1%5D+%2B+r%5B2%5D+\"$
\n" ); document.write( " $\"+r%5B1%5D%2Ar%5B2%5D+=+2+\"$
\n" ); document.write( "-----------------------------
\n" ); document.write( "Let $\"+r%5B2%5D+=+sqrt%283%29+-+1+\"$
\n" ); document.write( " $\"+r%5B1%5D+=+k+-+r%5B2%5D+\"$
\n" ); document.write( " $\"+r%5B1%5D+=+k+-+sqrt%283%29+-+1+\"$
\n" ); document.write( "------------------------------
\n" ); document.write( " $\"+r%5B1%5D%2Ar%5B2%5D+=+2+\"$
\n" ); document.write( " $\"+%28+-sqrt%283%29+%2B+%28+k-1+%29+%29%2A%28+sqrt%283%29+-+1+%29+=+2+\"$
\n" ); document.write( " $\"+-3+%2B+%28+k-1+%29%2Asqrt%283%29+%2B+sqrt%283%29+-+%28+k-1+%29+=+2+\"$
\n" ); document.write( " $\"+-3+%2B+k%2Asqrt%283%29+-+sqrt%283%29+%2B+sqrt%283%29+-+k+%2B+1+=+2+\"$
\n" ); document.write( " $\"+k%2Asqrt%283%29+-+k+=+4+\"$
\n" ); document.write( " $\"+k%2A%28+sqrt%283%29+-+1+%29+=+4+\"$
\n" ); document.write( " $\"+k+=+4%2F%28+sqrt%283%29+-+1+%29+\"$
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\n" ); document.write( "get another opinion, too. This is hard to prove.\r
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