document.write( "Question 1127908: 11. Breakfast Survey A dietitian read in a survey that at least 55% of adults do not eat breakfast at least 3 days a week. To verify this, she selected a random sample of 80 adults and asked them how many days a week they skipped breakfast. A total of 50% responded that they skipped breakfast at least 3 days a week. At a _ 0.10, test the claim. \n" ); document.write( "

Algebra.Com's Answer #744667 by Boreal(15235) $\"\"$ $\"About$

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z=(phat-p)/sqrt((p*(1-p)/n), assuming random sample, etc.
\n" ); document.write( "test stat is a z with critical value > |1.28|
\n" ); document.write( "z=-0.05/sqrt (.55*.45/80)=-0.05/0.0556=-0.899
\n" ); document.write( "This is less than the critical value, so there is insufficient evidence to reject the claim. p-value is 0.37 \n" ); document.write( "

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