document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128174>Question 1128174</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the remaining trigonometric ratios of &#952; based on the given information. <BR>\n" );
document.write( "csc &#952; = 2<BR>\n" );
document.write( "and cos &#952; is negative  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #744662 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=744662\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> csc=2<BR>\n" );
document.write( "sin=1/2<BR>\n" );
document.write( "sin is positive in 2nd quadrant and cos is negative<BR>\n" );
document.write( "sin (1/2) is at 150 degrees or (5/6)pi radians.<BR>\n" );
document.write( "cos at 150 is -sqrt(3)/2<BR>\n" );
document.write( "tangent is is -sqrt(3)/3<BR>\n" );
document.write( "ctn is -sqrt(3)<BR>\n" );
document.write( "sec is -(2/3) sqrt (3) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );