document.write( "Question 102466: My book doesn't give much help on solving this. Find the domain of f(x)3x+1/
\n" ); document.write( "x^2+4
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #74464 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=%283x%2B1%29%2F%28x%5E2%2B4%29\" Start with the given function\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4=0\" Set the denominator equal to zero. Remember, dividing by 0 is undefined. So if we find values of x that make the denominator zero, then we must exclude them from the domain.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2=-4\" Subtract 4 from both sides\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=0%2B-sqrt%28-4%29\" Take the square root of both sides\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since you cannot take the square root of a negative number and get a real number, the result will be imaginary\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So that means there are no real numbers which will make the denominator equal to zero\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the domain is: \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x is the element of all real numbers
\n" ); document.write( "
\n" );