document.write( "Question 1128104: Santiago receives ​$309 per year in simple interest from three investments. Part is invested at​ 2%, part at​ 3%, and part at​ 4%. There is​ $500 more invested at​ 3% than at​ 2%. The amount invested at​ 4% is six times the amount invested at​ 3%. Find the amount invested at each rate. Solve for the amount invested at each percent. \n" ); document.write( "
Algebra.Com's Answer #744594 by stanbon(75887)\"\" \"About 
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Santiago receives ​$309 per year in simple interest from three investments. Part is invested at​ 2%, part at​ 3%, and part at​ 4%. There is​ $500 more invested at​ 3% than at​ 2%. The amount invested at​ 4% is six times the amount invested at​ 3%. Find the amount invested at each rate. Solve for the amount invested at each percent.
\n" ); document.write( "Equations:
\n" ); document.write( "2t + 3r + 4f = 30900
\n" ); document.write( "r = t+500
\n" ); document.write( "f = 6*r
\n" ); document.write( "-------
\n" ); document.write( "Substitute and solve for \"r\"
\n" ); document.write( "2(r-500) + 3r + 24r = 30900
\n" ); document.write( "29r = 31900
\n" ); document.write( "r = $1100 (amt. invested at 3%)
\n" ); document.write( "f = 6r = $6600 (amt. invested at 4%)
\n" ); document.write( "t = r-500 = $500 (amt. invested at 2%)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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