document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128116>Question 1128116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write an equation in point-slope form of the line through the point (2, 3) perpendicular to the line with equation y=7/5x+4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #744577 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=744577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the slope of the line is 7/5, so the slope of the line perpendicular to it is -5/7, the negative reciprocal.<BR>\n" );
document.write( "point slope formula y-y1=m(x-x1), m slope, (x1, y1) point<BR>\n" );
document.write( "y-3=(-5/7)(x-2)<BR>\n" );
document.write( "y-3=-(5/7)x+10/7<BR>\n" );
document.write( "y=(-5/7)x+31/7<BR>\n" );
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