document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128064>Question 1128064</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Calculate	the	Binomial	distribution	for	the number	of	cars	recovered	if	the	probability	of	recovery	for	<BR>\n" );
document.write( "any	given	car	is	40%	and	5	cars	are	stolen </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #744533 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=744533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0 recovery is 0.60^5=0.078, probability of no recovery (0.6) to the 5th power.<BR>\n" );
document.write( "1 recovery is 5(0.4)*0.6)^4=0.259, the 5 is the number of ways it can occur.<BR>\n" );
document.write( "2 recoveries is 10*0.4^2*0.6^3=0.346<BR>\n" );
document.write( "3 recoveries is 10*0.4^3*0.6^2=0.230<BR>\n" );
document.write( "4 recoveries is 5*0.4^4*0.6=0.077<BR>\n" );
document.write( "5 recoveries is 0.4^5=0.01<BR>\n" );
document.write( "General form is nCr*p^r*(1-p)^(n-r) </SPAN>\n" );
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