document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128059>Question 1128059</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John's age is 3 times more than twice his younger brother's age. If the sum of their ages is at most 18, write an equation to express possible ages for John.\r<BR>\n" );
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document.write( "This is a question my Algebra 1 teacher has given me, I've tried every equation that I have thought of and every time she's told me I'm wrong. Please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #744529 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=744529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I assume you mean 3 more than twice his brother's age instead of 3 times more.<BR>\n" );
document.write( "Let x = the younger brother's age, y = John's age<BR>\n" );
document.write( "y = 3 + 2x -> x = y/2 - 3/2<BR>\n" );
document.write( "x + y <= 18 y <= 18 - x -> y <= 18 - y/2 + 3/2<BR>\n" );
document.write( "Solve the inequality for y:<BR>\n" );
document.write( "3y/2 <= 39/2<BR>\n" );
document.write( "y <= 13<BR>\n" );
document.write( "So John's age is less than or equal to 13<BR>\n" );
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