document.write( "Question 1128059: John's age is 3 times more than twice his younger brother's age. If the sum of their ages is at most 18, write an equation to express possible ages for John.\r
\n" ); document.write( "\n" ); document.write( "This is a question my Algebra 1 teacher has given me, I've tried every equation that I have thought of and every time she's told me I'm wrong. Please help
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Algebra.Com's Answer #744528 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
let's John's age be \"x\" and his brother's age be \"y\"\r
\n" ); document.write( "\n" ); document.write( "if John's age is \"3\" times \"more\" than \"twice\" his younger brother's age, we have (I guess it's \"3\" more, not \"3\" times\"more\")\r
\n" ); document.write( "\n" ); document.write( "\"x=2y%2B3\"...eq.1\r
\n" ); document.write( "\n" ); document.write( " If the sum of their ages is\"+at\" \"most\" \"18\", write an equation to express possible ages for John,\r
\n" ); document.write( "\n" ); document.write( "\"x%2By%3C=18\"....eq.2 ...(since given \"+at\" \"most\" \"18\")\r
\n" ); document.write( "\n" ); document.write( "now you can substitute \"x\" from eq.1 in eq.2 and solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"2y%2B3%2By%3C=18\"\r
\n" ); document.write( "\n" ); document.write( "\"3y%3C=18-3\"\r
\n" ); document.write( "\n" ); document.write( "\"y%3C=15%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"y%3C=5\"-> his brother's age is \"5\"\r
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\n" ); document.write( "\n" ); document.write( "now go to \"x=2y%2B3\"...eq.1 and find John's age\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2A5%2B3\"...eq.1\r
\n" ); document.write( "\n" ); document.write( "\"x=13\"->John's age\r
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