document.write( "Question 1128025: An executive would arrive 10.0 min early for an appointment if traveling at 60.0 mi/h, or 5.0 min early if traveling at 45.0 mi/h. How much time is there until the appointment?
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Algebra.Com's Answer #744487 by ikleyn(52814)\"\" \"About 
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document.write( "Let D be the distance to travel, in miles.\r\n" );
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document.write( "Then the time traveling at the speed of 60 mph is  \"D%2F60\" hours,\r\n" );
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document.write( "while the time traveling at the speed of 45 mph is  \"D%2F45\" hours. \r\n" );
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document.write( "We are given that the difference  \"D%2F45\"  - \"D%2F60\"   is 10 minutes - 5 minutes = 5 minutes = \"1%2F12\" of an hour:\r\n" );
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document.write( "    \"D%2F45\"  - \"D%2F60\"  = \"1%2F12\".\r\n" );
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document.write( "It is your basic equation, and the setup is just DONE.\r\n" );
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document.write( "To solve the equation, multiply its both sides by  180.  You will get\r\n" );
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document.write( "    4D - 3D = 15,\r\n" );
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document.write( "    D = 15    miles.\r\n" );
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document.write( "The appointment is scheduled at  \"15%2F60\" hours + 10 minutes = 15 minutes + 10  minutes = 25 minutes counting from the time\r\n" );
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document.write( "the executive starts his journey.\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see other similar solved problems,  look into the lesson\r
\n" ); document.write( "\n" ); document.write( "    - How far do you live from school? \r
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\n" ); document.write( "\n" ); document.write( "Your problem is non-standard and is different from that usually are offered in typical Math classes.\r
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\n" ); document.write( "\n" ); document.write( "Since you are interested in such kind of problems,  I recommend you to look into my other lessons on Travel & Distance
\n" ); document.write( "that you will find in accompanied references to that lesson.\r
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\n" ); document.write( "\n" ); document.write( "You will find there  A  LOT  of  unique  and  interesting   non-standard  Travel & Distance problems.\r
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