document.write( "Question 1127983: I am in serious need of help. How do i build a 95% confidence interval with only just orange M&M's? Number of M&Ms
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document.write( "ORANGE TOTAL
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document.write( "6 20
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document.write( "5 17
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document.write( "3 17
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document.write( "1 17
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document.write( "5 19
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document.write( "6 18
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document.write( "2 20
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document.write( "4 19
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document.write( "6 18
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document.write( "3 20
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document.write( "6 17
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document.write( "3 16
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document.write( "4 18
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document.write( "3 17
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document.write( "5 17
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document.write( "5 18
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document.write( "4 19
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document.write( "3 19
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document.write( "4 20
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document.write( "2 17
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document.write( "4 18
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document.write( "7 19
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document.write( "4 18
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document.write( "6 19
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document.write( "5 18
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document.write( "106 455
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document.write( " p-hat = 0.23
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document.write( " n = 455
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document.write( "Construct the 95% confidence interval around the true population porportion of orange colored M&Ms in a fun-sized bag of plain M&Ms.
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Algebra.Com's Answer #744465 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "For the standard normal distribution there is a \n" ); document.write( "\n" ); document.write( "In other words,\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so,\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Confidence Interval is: ( \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |