document.write( "Question 1080140: The temperature of air at 2000 metres is -8 degrees C. At ground level the temperature is 28 degrees C. The temperature changes at the same rate every 1000 metres. What is the temperature at the height of 2500 metres? \n" ); document.write( "
Algebra.Com's Answer #744461 by FrankM(1040)\"\" \"About 
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X=0, Y=28
\n" ); document.write( "X=2000 Y=-8\r
\n" ); document.write( "\n" ); document.write( "Change in Y (-36) over change in X (2000) = -36/2000\r
\n" ); document.write( "\n" ); document.write( "Y-Y1=m(X-X1)\r
\n" ); document.write( "\n" ); document.write( "Y-28=-36/2000(X)\r
\n" ); document.write( "\n" ); document.write( "Y= -.018X+28\r
\n" ); document.write( "\n" ); document.write( "At 2500, \r
\n" ); document.write( "\n" ); document.write( "Y=-.018(2500)+28\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Y= -17C
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