document.write( "Question 1127963: Five gallons of 20% alcohol solution is added to 3 gallons of 30% solution. Two gallons of pure alcohol is added to the resulting solution. What shall be its percentage of concentration of the final solution?
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Algebra.Com's Answer #744447 by ikleyn(52803)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Concentration of the mixture is the ratio of the volume of the pure alcohol to the total volume of liquid.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The volume of the pure alcohol in this case is\r\n" ); document.write( "\r\n" ); document.write( " 0.020*5 + 0.30*3 + 2 = 3 gallons.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The total volume of the liquid is\r\n" ); document.write( "\r\n" ); document.write( " 5 + 3 + 2 = 10 gallons.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The ratio (the concentration) is\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |