document.write( "Question 1127963: Five gallons of 20% alcohol solution is added to 3 gallons of 30% solution. Two gallons of pure alcohol is added to the resulting solution. What shall be its percentage of concentration of the final solution?
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Algebra.Com's Answer #744447 by ikleyn(52803)\"\" \"About 
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document.write( "Concentration of the mixture is the ratio of the volume of the pure alcohol to the total volume of liquid.\r\n" );
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document.write( "The volume of the pure alcohol in this case is\r\n" );
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document.write( "    0.020*5 + 0.30*3 + 2 = 3 gallons.\r\n" );
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document.write( "The total volume of the liquid is\r\n" );
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document.write( "    5 + 3 + 2 = 10 gallons.\r\n" );
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document.write( "The ratio (the concentration) is  \"3%2F10\", dimensionless value.\r\n" );
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document.write( "The percentage is  \"%283%2F10%29%2A100\" = 30%.\r\n" );
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document.write( "Answer.  The concentration of the final solution is 30%.\r\n" );
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