document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1127946>Question 1127946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please solve this question<BR>\n" );
document.write( " A former has 100 sheep and every sheep needs 1m2 of field on which to graze. He wants to make a rectangular field , using the smallest amount of fencing possible. What dimensions should he choose?\r<BR>\n" );
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document.write( "Regards </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #744399 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=744399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The smallest rectangle with the maximum surface area per unit perimeter is a square.<BR>\n" );
document.write( "Here, he needs 100 m^2 of field.<BR>\n" );
document.write( "the rectangle is x feet wide and y feet long.<BR>\n" );
document.write( "the area is xy sq ft, the perimeter is 2xy\r<BR>\n" );
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document.write( "xy=100, x=100/y<BR>\n" );
document.write( "perimeter is 2y+200/y<BR>\n" );
document.write( "The minimum is when the derivative is 0, or when 2-200/y^2=0<BR>\n" );
document.write( "2y^2=200<BR>\n" );
document.write( "y^2=100<BR>\n" );
document.write( "y=10, x=10<BR>\n" );
document.write( "the perimeter is 40 m, and the shape is a square.<BR>\n" );
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