document.write( "Question 1127890: A rock is thrown upward from a bridge that is 53 feet above a road. The rock reaches its maximum height above the road 0.61 seconds after it is thrown and contacts the road 3.25 seconds after it was thrown.\r
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document.write( "Write a Function (f) that determines the rock's height above the road (in feet) in terms of the number of seconds t since the rock was thrown.\r
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document.write( "f(t)=
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Algebra.Com's Answer #744396 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A rock is thrown upward from a bridge that is 53 feet above a road. The rock reaches its maximum height above the road 0.61 seconds after it is thrown and contacts the road 3.25 seconds after it was thrown.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Write a Function (f) that determines the rock's height above the road (in feet) in terms of the number of seconds t since the rock was thrown. \n" ); document.write( "---- \n" ); document.write( "Using 32 ft/sec/sec as acceleration of gravity: \n" ); document.write( "--- \n" ); document.write( "f(t) = -16t^2 + vt + 53 ---- v = speed upward at launch. \n" ); document.write( " \n" ); document.write( " |