document.write( "Question 1127869: The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.7 days and a standard deviation of 1.5 days.\r
\n" ); document.write( "\n" ); document.write( "What is the probability of spending more than 4 days in recovery?
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Algebra.Com's Answer #744365 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Compute the z score with x = 4, mu = 5.7 and sigma = 1.5
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\n" ); document.write( " which is approximate to 2 decimal places\r
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\n" ); document.write( "\n" ); document.write( "Use a table such as this one to find that \r
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\n" ); document.write( "\n" ); document.write( "note: look on page 1 for the row that starts with -1.1, then look at the column that has 0.03 at the top. This row and column intersect with the value 0.1292 inside\r
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\n" ); document.write( "\n" ); document.write( "So this means,
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\n" ); document.write( " -1.13) = 1-P(Z < -1.13) = 1-0.1292 = 0.8708\">
\n" ); document.write( " -1.13) = 0.8708\">
\n" ); document.write( "This is approximate to four decimal places\r
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\n" ); document.write( "\n" ); document.write( "Therefore,
\n" ); document.write( " 4) = 0.8708\">
\n" ); document.write( "which is also approximate\r
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\n" ); document.write( "\n" ); document.write( "Final Answer: 0.8708\r
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\n" ); document.write( "\n" ); document.write( "note: this answer is not entirely perfect due to some rounding errors accumulated. Use a calculator (instead of a table) to get more accurate answer. The reason I'm using a table is that a lot of professors require tables as they are found often in the back of your textbook.
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