document.write( "Question 102430: Joseph mixed a certain amount of 10% isopropyl mixture with 6o gallons of a 20% isopropyl solution and the resulting mixture is 16% isopropyl. How much of the 10% isopropyl did he add? \n" ); document.write( "
Algebra.Com's Answer #74434 by rossiv53(27)![]() ![]() ![]() You can put this solution on YOUR website! Ok, So let x = the amount of 10% mixture \n" ); document.write( "10%x +20%(60) = 16%(x+60) \n" ); document.write( ".10x +.20(60) = .16(x+60) \n" ); document.write( ".10x + 12 = .16x+9.60 \n" ); document.write( ".10x-.16x+12 = .16x-.16x+9.60 \n" ); document.write( "-.06x+12 = 9.60 \n" ); document.write( "-.06x+12-12 = 9.60-12 \n" ); document.write( "-.06x = -2.40 \n" ); document.write( "x = 40\r \n" ); document.write( "\n" ); document.write( "So, amount of 10% solution is 40 gallons\r \n" ); document.write( "\n" ); document.write( "Good luck! \n" ); document.write( " \n" ); document.write( " |