document.write( "Question 1127884: Clarifying - Looking to solve b here, the 0 after J is subscript:\r
\n" ); document.write( "\n" ); document.write( "\"+J0+=+%28%28%285b%5E4%29sqrt%283%29%29%2F16%29+\"
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Algebra.Com's Answer #744339 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"+J%5B0%5D+=+%28%28%285b%5E4%29sqrt%283%29%29%2F16%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"+16J%5B0%5D+=+5b%5E4%2Asqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"+16J%5B0%5D%2F5sqrt%283%29+=+b%5E4\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=root%284%2C+16J%5B0%5D%2F5sqrt%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=root%284%2C+2%5E4%2AJ%5B0%5D%2F5sqrt%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=2root%284%2C+J%5B0%5D%2F5sqrt%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=%282root%284%2CJ%5B0%5D%29%29%2F%28root%288%2C3%29%2Aroot%284%2C+5%29%29\"\r
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