document.write( "Question 1127814: A total of 5000 tickets were sold for a concert. Tickets were priced at $20, $30, and $50. If three times as many $20 tickets were sold as $50 tickets, and the total receipts were $140,000, how many tickets were sold at each price? \n" ); document.write( "

Algebra.Com's Answer #744274 by ikleyn(52786) $\"\"$ $\"About$

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document.write( "Let x = # of tickets sold at $50.\r\n" );
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document.write( "Then the number of tickets sold at $20 was 3x, according to the condition,\r\n" );
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document.write( "and the rest, (5000-x-3x) were sold at $30.\r\n" );
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document.write( "Therefore, your \"money\" equation is\r\n" );
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document.write( "50x + 20*(3x) + 30*(5000-x-3x) = 140000   dollars total  (the revenue !).\r\n" );
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document.write( "50x + 60x + 150000 - 120x = 140000\r\n" );
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document.write( "-10x = 140000 - 150000 = -10000\r\n" );
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document.write( "x =  = 1000.\r\n" );
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document.write( "Answer.  1000 tickets at $50;  3000 tickets at $20  and  1000 tickets at $30.\r\n" );
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