document.write( "Question 1127810: I have been working on this 2 hrs and I am exhausted mentally. Please help w this practice wk.\r
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\n" ); document.write( "\n" ); document.write( "A 10​% solution of fertilizer is to be mixed with a 60​% solution of fertilizer in order to get 150 gallons of a 50​% solution. How many gallons of the 10​% solution and 60​% solution should be​ mixed?
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Algebra.Com's Answer #744262 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
Wanted, 150 gallons of 50% fertilizer\r
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\n" ); document.write( "\n" ); document.write( "x gallons of the 60%
\n" ); document.write( "150-x gallons of the 10%\r
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\n" ); document.write( "\n" ); document.write( "\"60x%2B10%28150-x%29=50%2A150\"\r
\n" ); document.write( "\n" ); document.write( "Solve for x and evaluate 150-x.\r
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\n" ); document.write( "\n" ); document.write( "\"6x%2B%28150-x%29=50%2A15\"\r
\n" ); document.write( "\n" ); document.write( "\"5x%2B150=750\"\r
\n" ); document.write( "\n" ); document.write( "\"5x=600\"\r
\n" ); document.write( "\n" ); document.write( "\"x=120\"------gallons of the 60% fertilizer
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