document.write( "Question 1127594: You are in a boat 2 miles from the nearest point on the coast. You plan to travel to point Q, 3 miles down the coast and 1 mile inland. You row at 2 miles per hour and walk at 4 miles per hour. \r
\n" ); document.write( "\n" ); document.write( "(a) Write the total time T (in hours) of the trip as a function of the distance x (in miles).
\n" ); document.write( "(b) Determine the domain of the function.
\n" ); document.write( "(c) Use a graphing utility to graph the function. Be sure to choose an appropriate viewing window.
\n" ); document.write( "(d) Find the value of x that minimizes T.
\n" ); document.write( "(e) Write a brief paragraph interpreting these values.\r
\n" ); document.write( "\n" ); document.write( "I am not understanding this problem right now.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #744195 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "You didn't specify what the distance \"x\" is. I chose it to be the distance from the point on the shore closest to the boat to where the boat lands.

\n" ); document.write( "Then the distance rowing is \"sqrt%28x%5E2%2B4%29\" and the distance walking is \"sqrt%28%28x-3%29%5E2%2B1%29\".

\n" ); document.write( "Then, with the given rowing and walking speeds, the total time for the trip is

\n" ); document.write( "\"%28sqrt%28x%5E2%2B4%29%2F2%29%2B%28sqrt%28%28x-3%29%5E2%2B1%29%29%2F4\"

\n" ); document.write( "ANSWER a: \"T+=+%28sqrt%28x%5E2%2B4%29%2F2%29%2B%28sqrt%28%28x-3%29%5E2%2B1%29%29%2F4\"

\n" ); document.write( "ANSWER b: Algebraically, there are no restrictions on the domain of that function. However, logically the reasonable values for x should be between 0 and 3.

\n" ); document.write( "ANSWER c: A window of 0 to 3 for x and 1 to 2 for y produces a good graph.

\n" ); document.write( "ANSWER d: The minimum value of the function is when x=1.

\n" ); document.write( "ANSWER e: That is for you to do....
\n" ); document.write( "
\n" );