document.write( "Question 1127716: What are the zeros of the polynomial function?\r
\n" ); document.write( "\n" ); document.write( "\"+f%28x%29+=+x%5E4+-+4x%5E3+-+22x%5E2+%2B+4x+%2B+21+\"\r
\n" ); document.write( "\n" ); document.write( "Select EACH correct answer.\r
\n" ); document.write( "\n" ); document.write( "A. -3 \r
\n" ); document.write( "\n" ); document.write( "B. -1\r
\n" ); document.write( "\n" ); document.write( "C. 0\r
\n" ); document.write( "\n" ); document.write( "D. 1\r
\n" ); document.write( "\n" ); document.write( "E. 3\r
\n" ); document.write( "\n" ); document.write( "F. 7
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Algebra.Com's Answer #744191 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "0 can't be a root; if it were, the constant term would be 0.

\n" ); document.write( "Test 1 and -1 by evaluating the polynomial at those values. It turns out f(1)=0 and f(-1)=0, so both are roots. Roots of 1 and -1 correspond to binomial factors of x-1 and x+1; factor them out by factoring, long division, synthetic division, or any other method you know.

\n" ); document.write( "x^4-4x^3-22x^2+4x+21 = (x-1)(x+1)(x^2-4x-21)

\n" ); document.write( "The remaining quadratic is easily factored:

\n" ); document.write( "x^4-4x^3-22x^2+4x+21 = (x-1)(x+1)(x-7)(x+3)

\n" ); document.write( "The roots are 1, -1, -3, and 7.
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