document.write( "Question 1127709: While I can solve for y, I believe I'm missing something with the absolute value sign. There are pipes on the left side of the equation around the whole fraction. I think it changes the whole solution. Can someone elaborate please?\r
\n" ); document.write( "\n" ); document.write( "| \"+%282y%29%2F%28y%5E2+-1%29+\" | = 2
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Algebra.Com's Answer #744174 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\"+abs%282y%2F%28y%5E2+-1%29%29++=+2\" \r
\n" ); document.write( "\n" ); document.write( "\"+2abs%28y%2F%28y%5E2+-1%29%29++=+2\" \r
\n" ); document.write( "\n" ); document.write( "\"+abs%28y%2F%28y%5E2+-1%29%29++=+2%2F2\" \r
\n" ); document.write( "\n" ); document.write( "\"+abs%28y%2F%28y%5E2+-1%29%29++=+1\" \r
\n" ); document.write( "\n" ); document.write( "solutions: since abs value of the \"+y%2F%28y%5E2+-1%29+\" and \"+-%28y%2F%28y%5E2+-1%29%29+\" is same, we have\r
\n" ); document.write( "\n" ); document.write( "\"+y%2F%28y%5E2+-1%29++=+1\" or \"+-y%2F%28y%5E2+-1%29++=+1\"\r
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\n" ); document.write( "\"+y%2F%28y%5E2+-1%29++=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"+y++=+y%5E2+-1\"\r
\n" ); document.write( "\n" ); document.write( "\"++y%5E2-y+-1=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y+-+1%2F2%29%5E2+-+1%2F4-1+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"++%28y-1%2F2%29%5E2-5%2F4=0\"\r
\n" ); document.write( "\n" ); document.write( "\"++%28y-1%2F2%29%5E2=5%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"++%28y-1%2F2%29=sqrt%285%2F4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"++y=1%2F2%2B+sqrt%285%29%2F2\" \r
\n" ); document.write( "\n" ); document.write( "\"++y=%281%2F2%29%281%2B+sqrt%285%29%29\" or \"++y=%281%2F2%29%281-+sqrt%285%29%29\" \r
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