document.write( "Question 1127674: The reading speed of second grade students in a large city is approximately normal, with a mean of 89 words per minute (wpm) and a standard deviation of 10 wpm. Complete parts (a) through (e).
\n" );
document.write( "(a) What is the probability a randomly selected student in the city will read more than 93 words per minute?
\n" );
document.write( "The probability is
\n" );
document.write( "0.3446
\n" );
document.write( "(Round to four decimal places as needed.)
\n" );
document.write( "(b) What is the probability that a random sample of 13 second grade students from the city results in a mean reading rate of more than 93 words per minute? \n" );
document.write( "
Algebra.Com's Answer #744152 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The reading speed of second grade students in a large city is approximately normal, with a mean of 89 words per minute (wpm) and a standard deviation of 10 wpm. Complete parts (a) through (e). \n" ); document.write( "(a) What is the probability a randomly selected student in the city will read more than 93 words per minute? \n" ); document.write( "The probability is \n" ); document.write( "0.3446 \n" ); document.write( "(Round to four decimal places as needed.) \n" ); document.write( "0.3446 is correct \n" ); document.write( "z(93) = (93-89)/10 = 0.4 \n" ); document.write( "Ans:: P(x > 93) = P(z > 0.4) = normalcdf(0.4,100) = 0.3664 \n" ); document.write( "--------------------------------------------- \n" ); document.write( "(b) What is the probability that a random sample of 13 second grade from the city results in a mean reading rate of more than 93 words per minute? \n" ); document.write( "z(93) = (93-89)/(10/sqrt(13)) = sqrt(13)*0.4 = 1.4422 \n" ); document.write( "Ans: p(x-bar > 93) = P(z > 1.4422) = normalcdf(1.4422,100) = 0.0746 \n" ); document.write( "----- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------- \n" ); document.write( " \n" ); document.write( " |