document.write( "Question 1127683: Sandra has a total of one hundred fifty-one pennies, nickels and quarters. She has a total of $10.15. She has one more quarter than nickels and three times as many pennies as nickels. How many of each coin does she have?\r
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Algebra.Com's Answer #744139 by ikleyn(52798)\"\" \"About 
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\n" ); document.write( "Sandra has a total of one hundred fifty-one pennies, nickels and quarters. She has a total of $10.15.
\n" ); document.write( "She has one more quarter than nickels and three times as many pennies as nickels. How many of each coin does she have?\r
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\n" ); document.write( "\n" ); document.write( "            It is clear, from the first glance, that the problem is over-defined: it contains more data than it is required for the solution.\r
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document.write( "Let N be the number of nickels.\r\n" );
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document.write( "Then the number of quarters is (N+1)  and the number of pennies is 3N.\r\n" );
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document.write( "Your \"coin\" equation is  \r\n" );
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document.write( "    N + (N+1) + 3N = 151.\r\n" );
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document.write( "    5N + 1 = 151\r\n" );
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document.write( "    5N = 151-1 = 150  ====>  N = 150/5 = 30.\r\n" );
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document.write( "So far, we got  30 nickels, 31 quarter and 3*30 = 90 pennies.\r\n" );
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document.write( "CHECK.   30*5 + 31*25 + 90 = 10.15 cents.    !  Correct !\r\n" );
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document.write( "         The input data is consistent; the solution is correct.\r\n" );
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document.write( "Answer.  30 nickels, 31 quarter and 90 pennies.\r\n" );
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