document.write( "Question 1127661: Find the dimensions of the box described.
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document.write( "The length is 4 inches more than the width. The width is 3 inches more than the height. The volume is 480 cubic inches.\r
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Algebra.Com's Answer #744120 by FrankM(1040)![]() ![]() You can put this solution on YOUR website! H=X W=X+3 L=X+7\r \n" ); document.write( "\n" ); document.write( "LWH = X^3+10X^2+21X=480 so\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " X^3+10X^2+21X-480=0 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using a bit of guess and check, we easily find X=5 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(Note, X has to be positive, and at 1, we get 32-480, very negative. Jumping to 3, we have 27+90+63-480= -300, so we jump to 5 and see 125+250+105-480=0)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5 * 8 * 12 =480 \n" ); document.write( " |