document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102426>Question 102426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I looked over my notes several times, but I still have trouble setting up the problem and solving it. I'm not even sure I have this under the right category. This is being solved using a Quantity-Value Table.\r<BR>\n" );
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document.write( "Juan has coffee that sells for $9 a pound and $4 a pound. How many pounds of each must be mixed to get 20 pounds of coffee worth $8.25 a pound?\r<BR>\n" );
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document.write( "I know the table is set up as Q|V|Q*V. What I tried using was x*4, x*9, and 20*8.25. I'm not sure I have it set up correctly. Then I got to 9x+4x=165. Solve and get x = 165/13. I know I'm supposed to apply that answer to get the resulting answer for both the $9 a pound and $4 a pound, but I'm not sure how.\r<BR>\n" );
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document.write( "Please and thank you for any help you can give! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74412 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Juan has coffee that sells for $9 a pound and $4 a pound. How many pounds of each must be mixed to get 20 pounds of coffee worth $8.25 a pound? <BR>\n" );
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document.write( "Let amt. of $9 coffee be \"x\" ; Value of this is 9x dollars<BR>\n" );
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document.write( "Amt. of $4 coffee is \"20-x\" ; value of this is 4(20-x)= 80-4x dollars<BR>\n" );
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document.write( "Amt of mixture = 20 lbs ; value of this is 8.25*20 = 165 dollars<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "9x + 80-4x = 165<BR>\n" );
document.write( "5x = 85<BR>\n" );
document.write( "x =17 lbs (amount of $9 coffee in the mixture)<BR>\n" );
document.write( "20-x = 3 lbs (amount of $4 coffee in the misture)\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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