document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1127671>Question 1127671</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first three terms of a G.P are x+1, x+3 and x+8, find,<BR>\n" );
document.write( "i) The Value of x<BR>\n" );
document.write( "ii) The common ratio<BR>\n" );
document.write( "iii) The sum of the first 15 terms. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #744119 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=744119\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The common ratio r = (x+3)/(x+1) = (x+8)/(x+3)<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "x^2 + 6x + 9 = x^2 + 9x + 8<BR>\n" );
document.write( "3x = 1<BR>\n" );
document.write( "x = 1/3<BR>\n" );
document.write( "Therefore r = (1/3 + 3)/(1/3 + 1) = 10/4<BR>\n" );
document.write( "The sum of the first n terms of a G.P. = Sn = a1*(1-r^n)/(1-r)<BR>\n" );
document.write( "S15 = (4/3)(1-(10/4)^15/(1-(10/4)) = 827841.4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );