document.write( "Question 1127660: Find the dimensions of the box described.
\n" ); document.write( "The length is twice as long as the width. The height is 4 inches greater than the width. The volume is 48 cubic inches. \n" ); document.write( "

Algebra.Com's Answer #744109 by math_helper(2461) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"+LWH+=+48+\"$
\n" ); document.write( "Using L=2W and H=W+4:
\n" ); document.write( " $\"+%282W%29%28W%29%28W%2B4%29+=+48+\"$
\n" ); document.write( " $\"++2W%5E3+%2B+8W%5E2+=+48+\"$
\n" ); document.write( " $\"++W%5E3+%2B+4W%5E2+-+24+=+0+\"$
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\n" ); document.write( "\n" ); document.write( "The only real valued solution is W=2 \r
\n" ); document.write( "\n" ); document.write( "W=2 Ч> L=4
\n" ); document.write( "W=2 Ч> H=6\r
\n" ); document.write( "\n" ); document.write( "ЧЧ
\n" ); document.write( "Ans: W=2in, L=4in, H=6in
\n" ); document.write( "ЧЧ\r
\n" ); document.write( "\n" ); document.write( "Check: 2*4*6 = 48 \r
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