document.write( "Question 102403This question is from textbook
\n" ); document.write( ": 2 times sq. root of x minus sq. root of 2x+1=1 \n" ); document.write( "
Algebra.Com's Answer #74406 by edjones(8007)\"\" \"About 
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2sqrt(x)-sqrt(2x+1)=1
\n" ); document.write( "2sqrt(x)-1=sqrt(2x+1)
\n" ); document.write( "4x-4sqrt(x)+1=2x+1 square both sides
\n" ); document.write( "-4sqrt(x)=-2x subtract 4x+1 from each side.
\n" ); document.write( "16x=4x^2 square both sides
\n" ); document.write( "4x^2-16x=0 subtract 16x from each side.
\n" ); document.write( "4x(x-4)=0 factor
\n" ); document.write( "x=0, x=4
\n" ); document.write( "Check:
\n" ); document.write( "2sqrt(0)-sqrt(0+1)=1...-1=1 false so x=0 is not an answer.
\n" ); document.write( "2sqrt(4)-sqrt(2*4+1)=1...2*2-3=1 true so x=4 is the only answer.
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