document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1127599>Question 1127599</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x is inversely proportional to the cube of z. What happens to x when z is halved? \r<BR>\n" );
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document.write( "I know x=K/z^3 but I do not know how to continue from there. Could you please explain what steps to take next?\r<BR>\n" );
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document.write( "My professor used \"new\" and \"old\" and I am very confused. His solution was Znew=z old/2<BR>\n" );
document.write( "x new=K/z^3new = K/(8 old/2)^3 = 8K/z old^3 = 8 x old\r<BR>\n" );
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document.write( "There must be a more simple way to explain/solve this sort of problem?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #744024 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=744024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is increased by a factor of 8.<BR>\n" );
document.write( "pick some numbers<BR>\n" );
document.write( "x=k/z^3, let x=8 when z=4<BR>\n" );
document.write( "8=k/64; k=512<BR>\n" );
document.write( "Let z now be 2<BR>\n" );
document.write( "x=512/8=64.  That is 8 times the original x<BR>\n" );
document.write( "it is 1/z^3, and when z is half of that it is 1/(1/8) or 8.\r<BR>\n" );
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document.write( "When z is decreased by (1/2), x is increased by 1/(1/2)^3 or 8 fold.  </SPAN>\n" );
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