document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1127225>Question 1127225</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Eliana wants to make a diorama for an art contest. She starts with a rectangular sheet of cardboard that is 12 in. long and 8 in. wide. She plans to make the diorama box by cutting identical squares from the corners and folding the sides to create a box with an open front, as shown below. \r<BR>\n" );
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document.write( "http://i66.tinypic.com/el4cjm.jpg\r<BR>\n" );
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document.write( "Eliana wants her diorama box to have the maximum allowable volume of 36 in ^3. <BR>\n" );
document.write( "Determine all the possible lengths Eliana can use with the volume of 36 in ^3. Round dimensions to nearest hundredth of an inch. \r<BR>\n" );
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document.write( "In the diagram (http://i66.tinypic.com/el4cjm.jpg) x represents the side length of the squares Eliana will cut from each corner. Which dimension of the diormama box does x represent: the length or the width of the box, or the depth of the box from front to back? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #744017 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=744017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the volume is x (the height or depth)(12-2x)(8-2x)<BR>\n" );
document.write( "that is 4x^3*40x^2+96x<BR>\n" );
document.write( "and that equals 36<BR>\n" );
document.write( "x=0.46 in and x=3 in<BR>\n" );
document.write( "Lengths can be 6 inches (12-2(3)) and 11.08, with width 3 in<BR>\n" );
document.write( "corresponding widths would be 2 and 7.08, with width 0.46 in\r<BR>\n" );
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