document.write( "Question 1127565: A plane flies into the wind (against the wind current) for 3.5 hours for a distance of 1,260 miles. The return trip with a tailwind (with the wind current) only takes 3 hours. Find the average speed of the plane in still air and the speed of the wind current. \n" ); document.write( "
Algebra.Com's Answer #743982 by josgarithmetic(39799)\"\" \"About 
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\"system%28r-w=1260%2F3.5%2Cr%2Bw=1260%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "-\r
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\n" ); document.write( "\n" ); document.write( "\"w%2B1260%2F3.5=-w%2B1260%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"2w=1260%2F3-1260%2F3.5\"\r
\n" ); document.write( "\n" ); document.write( "\"2w=60\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28w=30%29\"---------speed of wind\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28390=r%29\"--------speed of plane in absence of wind
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