document.write( "Question 1127534: On a typical day in the fall, the scenic riverboat tour travels 11 miles upstream against a 3 mph current. In the spring, the current runs 2 mph faster than in the fall, and the same upstream trip takes twice as long. What is the speed of the boat in still water? \n" ); document.write( "

Algebra.Com's Answer #743962 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Let x = the speed of the boat in still water, in miles per hour.\r\n" );
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document.write( "Then in the fall, the time upstream is   hours.\r\n" );
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document.write( "     in the spring, the time upstream is   hours.\r\n" );
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document.write( "The time equation is\r\n" );
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document.write( "     = .\r\n" );
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document.write( "Cancel 11 in both sides\r\n" );
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document.write( "     = .\r\n" );
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document.write( "    2*(x-5) = x - 3\r\n" );
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document.write( "    2x - 10 = x - 3\r\n" );
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document.write( "    x = 10-3 = 7.\r\n" );
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document.write( "Answer.  The speed of the boat in still water is  7 miles per hour.\r\n" );
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document.write( "CHECK.  The spring time is   =  = 5.5 hours;\r\n" );
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document.write( "        The fall time is   =  = 2.75 hours.\r\n" );
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document.write( "        The spring time is twice the fall time.    ! Correct !\r\n" );
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