document.write( "Question 1127541:  if a rocket is fired vertically into the air with a speed of 240 feet per second,it's height at time t seconds is given by h= -16t^2 + 240t. at the time will the rocket be 704 feet above the ground.
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| Algebra.Com's Answer #743946 by FrankM(1040)     You can put this solution on YOUR website! 704=-16t^2+240t\r \n" ); document.write( "\n" ); document.write( "-16t^2+240t-704=0 (divide thru by -16)\r \n" ); document.write( "\n" ); document.write( "t^2-15t+44=0\r \n" ); document.write( "\n" ); document.write( "(t-11)(t-4)\r \n" ); document.write( "\n" ); document.write( "Ans at t=4 and t=11\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |