document.write( "Question 1127528: Determine algebraically whether the function f(x)=x^3-2x+1 is odd, even, or neither \n" ); document.write( "
Algebra.Com's Answer #743934 by MathLover1(20849)\"\" \"About 
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To do this, you take the function and plug \"-x\" in for \"x\", and then \"simplify\".
\n" ); document.write( "If you end up with the exact same function that you started with (that is, if \"f+%28-x%29+=+f+%28x%29\", so all of the signs are the same), then the function is \"even\".
\n" ); document.write( "If you end up with the exact opposite of what you started with (that is, if \"f+%28-x%29+=+-f+%28x%29\", so all of the signs are switched), then the function is \"odd\".\r
\n" ); document.write( "\n" ); document.write( "In all other cases, the function is \"\"neither\" even nor odd\".\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+x%5E3+-+2+x+%2B+1+\"
\n" ); document.write( "\"f%28-x%29+=+%28-x%29%5E3+-+2+%28-x%29+%2B+1+\"
\n" ); document.write( "\"f%28-x%29+=+-x%5E3+%2B+2+x+%2B+1\"
\n" ); document.write( "\"f+%28-x%29+%3C%3E+f+%28x%29\" =>is not an \"even\" function\r
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\n" ); document.write( "\n" ); document.write( "check if \"f+%28-x%29+=+-f+%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28-x%29+=+-%28x%5E3+-2+x+%2B+1%29+%0D%0A%7B%7B%7Bf%28-x%29+=+-x%5E3+%2B2+x+-+1+\"\r
\n" ); document.write( "\n" ); document.write( "so, \"f+%28-x%29%3C%3E+-f+%28x%29\" =>is not an \"odd+\" function\r
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\n" ); document.write( "\n" ); document.write( "so, answer is: \"neither\"\r
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