document.write( "Question 1127489: x^2 −y^2 + mx + 5y − 6 = (ax + by +c)(dx + ey + f). Determine the values for a, b, c, d, e, f, and m. \n" ); document.write( "
Algebra.Com's Answer #743925 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"x%5E2+-y%5E2+%2B+mx+%2B+5y+-6+=+%28ax+%2B+by+%2Bc%29%28dx+%2B+ey+%2B+f%29\"...first multiply right side of equation\r
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\n" ); document.write( "\n" ); document.write( "compare coefficients and you see that:\r
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\n" ); document.write( "\n" ); document.write( "\"ad=1\"->only when \"a=1\" and \"d=1\"\r
\n" ); document.write( "\n" ); document.write( "\"be=-1\"->only when \"b=-1\" and \"e=1\"\r
\n" ); document.write( "\n" ); document.write( "\"-m=af%2Bcd\"....since \"a=1\" and \"d=1\"\r
\n" ); document.write( "\n" ); document.write( "\"-m=f%2Bc\"....eq.1\r
\n" ); document.write( "\n" ); document.write( "\"ae%2Bbd=0\" since there is no \"xy\" term on left side\r
\n" ); document.write( "\n" ); document.write( "\"cf=-6\" ...only if \"c=3\" and \"f=-2\" or \"c=1\" and \"f=-6\" or vice versa\r
\n" ); document.write( "\n" ); document.write( "I will go with \"c=3\" and \"f=-2\"\r
\n" ); document.write( "\n" ); document.write( "then \r
\n" ); document.write( "\n" ); document.write( "\"-m=f%2Bc\"....eq.1
\n" ); document.write( "\"-m=-2%2B3\"
\n" ); document.write( "\"-m=1\"
\n" ); document.write( "\"m=-1\"\r
\n" ); document.write( "\n" ); document.write( "so, your solutions are:
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\n" ); document.write( "\"a=1\"
\n" ); document.write( "\"b=-1\"
\n" ); document.write( "\"c=3\"
\n" ); document.write( "\"d=1\"
\n" ); document.write( "\"e=1\"
\n" ); document.write( "\"f=-2\"
\n" ); document.write( "\"m=-1\"\r
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