document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1127108>Question 1127108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose your manager indicates that for a normally distributed data set you are analyzing, your company wants data points between <BR>\n" );
document.write( "z<BR>\n" );
document.write( "=<BR>\n" );
document.write( "&#8722;<BR>\n" );
document.write( "1.6<BR>\n" );
document.write( "z=-1.6<BR>\n" );
document.write( "and <BR>\n" );
document.write( "z<BR>\n" );
document.write( "=<BR>\n" );
document.write( "1.6<BR>\n" );
document.write( "z=1.6<BR>\n" );
document.write( "standard deviations of the mean (or within 1.6 standard deviations of the mean). What percent of the data points will fall in that range? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #743920 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=743920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is about 90%, since +/-1.645 is z-value for 90% CI.\r<BR>\n" );
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document.write( "The actual per cent is 89.0%. </SPAN>\n" );
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