document.write( "Question 1127464: A company can sell 2000 magazine subscriptions at $40 each. For each $5 increase in the price, it will sell 200 fewer subscriptions. What subscription price will provide the maximum revenue for the company?
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Algebra.Com's Answer #743890 by josgarithmetic(39630) $\"\"$ $\"About$

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That also means, for every 1 dollar price increase, $\"200%2F5\"$ fewer subscriptions.\r
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document.write( "PRICE         HOW MANY SUBSCRIPTIONS\r\n" );
document.write( "40              2000\r\n" );
document.write( "400+d          2000-(200/5)d\r\n" );
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document.write( "for d number of dollars\r\n" );
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\n" ); document.write( "\n" ); document.write( "Revenue, $\"%2840%2Bd%29%282000-%28200%2F5%29d%29\"$ .\r
\n" ); document.write( "\n" ); document.write( "You want to find the maximum of this revenue and the corresponding d number of dollars to add or subtract for this maximum d.\r
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\n" ); document.write( "\n" ); document.write( " $\"40%2840%2Bd%29%2850-d%29\"$ \r
\n" ); document.write( "\n" ); document.write( "zeros at d of -40, and +50.\r
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\n" ); document.write( "\n" ); document.write( " $\"%28-40%2B50%29%2F2=10%2F2=highlight_green%285%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "This means, best revenue is for $\"40%2B5=highlight%2845%29\"$ dollars.
\n" ); document.write( "This max revenue, $\"40%2A45%2A45=highlight%2881000%29\"$ \n" ); document.write( "

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