document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1127466>Question 1127466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find &#952;, 0° &#8804; &#952; < 360°, given the following information.<BR>\n" );
document.write( "cos &#952; = &#8722; squr(3)/2 and &#952; in QII\r<BR>\n" );
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document.write( "&#952; =       ° </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #743882 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=743882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find &#952;, 0° &#8804; &#952; < 360°, given the following information.<BR>\n" );
document.write( "cos &#952; = &#8722; squr(3)/2 and &#952; in QII <BR>\n" );
document.write( "------<BR>\n" );
document.write( "Sketch a 30-60 degree right triangle<BR>\n" );
document.write( "Let the side opposite the 30 deg angle be 1<BR>\n" );
document.write( "Then the hypotenuse is 2<BR>\n" );
document.write( "And the base is sqrt(3)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "So the cos(30) = sqrt(3)/2<BR>\n" );
document.write( "------<BR>\n" );
document.write( "For your problem the reference angle is arccos(sqrt(3)/2) = 30 degrees<BR>\n" );
document.write( "----<BR>\n" );
document.write( "In QII theta = 180+30 = 210 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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