document.write( "Question 1127465: Find θ, 0° ≤ θ < 360°, given the following information.
\n" ); document.write( "cot θ = square root3/3
\n" ); document.write( " and θ in QIII
\n" ); document.write( "θ = ° \n" ); document.write( "

Algebra.Com's Answer #743879 by stanbon(75887) $\"\"$ $\"About$

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Find θ, 0° ≤ θ < 360°, given the following information.
\n" ); document.write( "cot θ = square root3/3 = 1/sqrt(3)
\n" ); document.write( "So theta = tan^-1(sqrt(3)) = 60 degrees (this is the reference angle)
\n" ); document.write( "and θ in QIII is 180+60 = 240 degrees
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "

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