document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1127452>Question 1127452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x:\r<BR>\n" );
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document.write( "a) ln(2x+1)=4\r<BR>\n" );
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document.write( "b) e^3x+1+2+7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #743858 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=743858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solving for ln(2x + 1) = 4<BR>\n" );
document.write( "Apply the log rule: <BR>\n" );
document.write( "a = log_b(b^a)<BR>\n" );
document.write( "4 = ln(e^4)<BR>\n" );
document.write( "ln(2x + 1) = ln(e^4)<BR>\n" );
document.write( "2x + 1 = e^4<BR>\n" );
document.write( "x = (e^4-1)/2 this is your answer<BR>\n" );
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document.write( "Solving for e^3x+1+2+7<BR>\n" );
document.write( "add the numbers; 1 + 2 + 7 = 10<BR>\n" );
document.write( "= e^3x + 10 This is your answer\r<BR>\n" );
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document.write( "Happy learning! </SPAN>\n" );
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