document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1127429>Question 1127429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An old jar of dimes and quarters contains 200 coins total, and the value of all the coins is $24.50. How many quarters are in the jar? \r<BR>\n" );
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document.write( "A. 50 <BR>\n" );
document.write( "B. 130 <BR>\n" );
document.write( "C. 127 <BR>\n" );
document.write( "D. 150 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #743830 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=743830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d + q = 200 therefore d = 200-q<BR>\n" );
document.write( "0.10d + 0.25q = 24.50 substitute for d:<BR>\n" );
document.write( "0.10(200-q) + 0.25q = 24.50<BR>\n" );
document.write( "20 - 0.10q + 0.25q = 24.50<BR>\n" );
document.write( "0.15q = 4.50<BR>\n" );
document.write( "q = 30 there are 30 quarters in the jar </SPAN>\n" );
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