document.write( "Question 1127415: Th base of an isosceles triangle is 2 root2 cm. If the medians to the equal sides intersect at right angles, then the height of the triangle, in cm, is \n" ); document.write( "

Algebra.Com's Answer #743829 by ikleyn(52800) $\"\"$ $\"About$

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\n" ); document.write( " $\"highlight%28cross%28Th%29%29\"$ The base of an isosceles triangle is 2 root2 cm.
\n" ); document.write( "If the medians to the equal sides intersect at right $\"highlight%28cross%28angles%29%29\"$ angle, then the height of the triangle, in cm, is
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document.write( "The two intersecting medians and the base of the given triangle form an isosceles right triangle with the hypotenuse of  centimeters.\r\n" );
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document.write( "Hence, the altitude of this isosceles right triangle drawn to its hypotenuse is exactly HALF of the base, i.e.  centimeters.\r\n" );
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document.write( "Next, the length of this altitude is exactly one third of the height of the given triangle; \r\n" );
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document.write( "so, the height of the given isosceles triangle is  centimeters.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "I am glad that you seriously took my criticism of the previous version of this problem, which was presented incorrectly\r
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\n" ); document.write( "\n" ); document.write( "https://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.1127346.html\r
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\n" ); document.write( "\n" ); document.write( "In this version those deficiencies are fixed, which is GOOD.\r
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