document.write( "Question 1127422: A boat has a speed of 15 mph in still water. It travels downstream from Greentown to Glenavon in g hours. It then goes back upstream from Glenavon to Cambria, which is 2 miles downstream from Greentown, in g hours. Find the rate of the current. \n" ); document.write( "

Algebra.Com's Answer #743827 by ikleyn(52858) $\"\"$ $\"About$

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document.write( "The distance from Greentown to Glenavon is  D1 = g*(15+x) miles downstream.\r\n" );
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document.write( "The distance from Glenavon to Cambria is  D2 = g*(15-x)  miles upstream.\r\n" );
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document.write( "The difference D1 - D2 is 2 miles, according to the condition.\r\n" );
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document.write( "It gives you an equation\r\n" );
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document.write( "g*(15+x) - g*(15-x) = 2,\r\n" );
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document.write( "which you can easily solve and find \"x\", the rate of the current.\r\n" );
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document.write( "x =  miles per hour.\r\n" );
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