document.write( "Question 1127339: A number of two digits exceeds five times the sum of it a digits by 9 and its ten digit exceeds its unit digit by 1 find the number \n" ); document.write( "
Algebra.Com's Answer #743737 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the 10s digit and represent the 1s digit.\r
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\n" ); document.write( "\n" ); document.write( "The number is then \r
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\n" ); document.write( "\n" ); document.write( "The sum of the digits is \r
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\n" ); document.write( "\n" ); document.write( "And the digits differ by 1, so \r
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\n" ); document.write( "\n" ); document.write( "That makes the sum of the digits \r
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\n" ); document.write( "\n" ); document.write( "And the number itself \r
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\n" ); document.write( "\n" ); document.write( "Since the number is 9 more than five times the sum of the digits:\r
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\n" ); document.write( "\n" ); document.write( "Solve for to get the 10s digit and then calculate to get the 1s digit.
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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