document.write( "Question 1127027: To a motor-cyclist traveling due north at 50km/hr, the wind appear to come from north west at 60km/hr, what is the true velocity of the wind \n" ); document.write( "
Algebra.Com's Answer #743723 by ikleyn(52788)\"\" \"About 
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document.write( "1.  Let's consider more simple case first:\r\n" );
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document.write( "        Let there is no wind at the coordinate system which rests relative the Earth,\r\n" );
document.write( "        and a motor-cyclist travels due North at 50 km/h.\r\n" );
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document.write( "    Then it is clear that he/she will observe the wind due to south at 50 km/h.\r\n" );
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document.write( "    I other words, he/she will observe the wind with the vector  (0,-50)  (the units of speed are in km/h).\r\n" );
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document.write( "2.  Then it is clear, that if there is the wind with the velocity vector  W \r\n" );
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document.write( "    in the coordinate system which rests relative the Earth surface, and \r\n" );
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document.write( "    the motor-cyclist moves at the speed  M  (! M is vector !), then the wind he/she will observe is \"W%5Bobserved%5D\" = W - M.\r\n" );
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document.write( "3.  With these explanations, we have \r\n" );
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document.write( "        - the vector  M = (0,50) of the motor-cyclist speed relative the Earth;\r\n" );
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document.write( "        - the vector  \"W%5Bobserved%5D\" = (\"60%2A%28sqrt%282%29%2F2%29\",\"-60%2A%28sqrt%282%29%2F2%29\")\r\n" );
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document.write( "         - and the equation  \"W%5Bobserved%5D\" = (\"60%2A%28sqrt%282%29%2F2%29\",\"-60%2A%28sqrt%282%29%2F2%29\") = W - (0,50).\r\n" );
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document.write( "    From this equation, the \"real\" vector of the wind velocity in the resting coordinate system is\r\n" );
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document.write( "        W = (\"60%2A%28sqrt%282%29%2F2%29\",\"-60%2A%28sqrt%282%29%2F2%29\") + (0,50) = (\"60%2A%28sqrt%282%29%2F2%29\",\"-60%2A%28sqrt%282%29%2F2%29%2B50\").\r\n" );
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document.write( "    Now, when you know the vector W by its components, you can easily calculate its magnitude.\r\n" );
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document.write( "    It is just arithmetic, and I leave it to you to complete this assignment on your own.\r\n" );
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