document.write( "Question 1127226: In △ABC, m∠CAB = 60° and point D∈BC so that AD=10 in and the distance from D to AB is 5 in. Prove that AD is the angle bisector of ∠A. \n" ); document.write( "
Algebra.Com's Answer #743708 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "If AD is 10 and the distance from D to AB is 5, then triangle ABD is a 30-60-90 right triangle, with the 30-degree angle at A. \n" ); document.write( "(My sketch has AB horizontal, with B to the right of A; AD slanting up to the right from A; DB perpendicular to AB.) \n" ); document.write( "Since angle A is 60 degrees, AD bisects it. \n" ); document.write( " |