document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1127310>Question 1127310</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume the acceleration of the object is a(t) = &#8722;32 feet per second per second. (Neglect air resistance.)<BR>\n" );
document.write( "A ball is thrown vertically upward from a height of 5 feet with an initial velocity of 72 feet per second. How high will the ball go?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #743706 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=743706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> using a(t) = -32ft/s^2<BR>\n" );
document.write( "a(t) = -32ft/s^2 --> v(t) = &#8747;-32dt --> v(t) = -32t + C<BR>\n" );
document.write( "v(0) = 72 --> v(0) = -32(0)+C = 72 so our velocity function is:<BR>\n" );
document.write( "v(t) = -32t+72 --> at the maximum height the velocity will be zero, so we can restate:<BR>\n" );
document.write( "0 = -32t+72 --> t = 2.25 <BR>\n" );
document.write( "Now, to find the maximum height<BR>\n" );
document.write( "s(t) = &#8747;v(t)dt = &#8747;(-32t+ 72)dt =<BR>\n" );
document.write( "sorry I've run out of time. Maybe the above will help you find the answer </SPAN>\n" );
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