document.write( "Question 102326: How much antifreeze must be added to a 10 gallon of 20% antifreeze to make 50% antifreeze solution? \n" ); document.write( "

Algebra.Com's Answer #74370 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
10 gallons of 20% antifreeze have $\"10+x+20%2F100\"$ or $\"2\"$ gallons of antifreeze, that's 20% antifreeze, 80% water.
\n" ); document.write( "So you currently have 2 gallons of antifreeze and 8 gallons of water.
\n" ); document.write( "For a 50% solution, you need 50% water and 50% antifreeze.
\n" ); document.write( "You have 8 gallons of water so you need 8 gallons of antifreeze for a 50% solution.
\n" ); document.write( "You have 2 gallons of antifreeze.
\n" ); document.write( "You need 8 gallons of antifreeze.
\n" ); document.write( "You need to add $\"8-2+\"$ gallons of antifreeze.
\n" ); document.write( "Your answer is 6 gallons. \n" ); document.write( "

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